I have the answer to this problem, but I'm having trouble figuring out how to find the answer. Here's the problem: The volumes of two similar solids are 1331m cubed and 216m cubed. The surface area of the larger one is 1089m squared. What is the surface area of the smaller one? When I worked this problem, I got 177m squared, but the correct answer is "none of these" on the sheet... so I'm not really sure what the exact answer is supposed to be...
2007-05-13 12:39:45 · 2 answers · asked by Anonymous in Education & Reference ➔ Homework Help
I got very close to your answer...
Volume 1 = 1331
Surface area 1 = 1089
Volume 2 = 216
Surface area 2 = x
So, 1331:216 as 1089 is to x
You could use a fraction as well...
1331/1089 = 216 / x
Now you cross multiply...
(216)(1089) = 1331x
235224 / 1331 = x
x = 176.72
Perhaps your teacher doesn't want you to round off.
2007-05-13 13:02:11 · answer #1 · answered by mysstere 5 · 0⤊ 0⤋
Try this proportion
((1331^(2/3))/(216^(2/3)) = 1089/x
121/36 =1089/x
Cross multiply and you get
x = 324 m²
What I did was to get the cubic volume ratios into quadratic form as areas are.
So I took the cube root of the volumes then squared them to set up the proportion.
.
2007-05-13 13:10:43 · answer #2 · answered by Robert L 7 · 0⤊ 0⤋