Why does factoring have to be evil to me? Its IMPOSSIBLE?

Question

Grrr....It takes me 40mins to just finish a 30problem factoring. That means 3:4, 3 problems for every 4mins thats long.
Okay, heres an equation that consists of the constant and the coeffiecients of factoring. I have the anwsers but I want to know how to do i, well you help me?

x^4-y^4=(x^2+y^2)(x^2-Y^2)--->(x^2+y^2)(x+y)(x-y) Why does it have to be like this?


Lastly, 2x^3+7x^2+5x=?

Answer 1

x^4-y^4=(x^2+y^2)(x^2-Y^2)
One more step since x^2-y^2 can be factored
= (x^2+y^2)(x+y)(x-y)

2x^3+7x^2+5x = x(2x^2+7x+5)
factoring the x out of every term
= x(2x+5)(x+1)
factoring the remaining term

Answer 2

For most standard factoring problems use my calculator at http://www.poodwaddle.com/mathfactor.html Your last problem is a simple factoring problem once you divide out the common term x
x(2x^2 + 7x +5) Plug it into my calc and see what you get

Answer 3

x^4-y^4=(x^2+y^2)(x^2-Y^2)
=(x^2+y^2)(x-y)(x+y)

2x^3+7x^2+5x=x(2x^2+7x+5)
=x(2x+5)(x+1)