a coin is tossed 8 times calculate the probability of tossing a) 6 heads and 2 tails and b) 7 heads and 1 tail
2007-05-13 12:19:32 · 3 answers · asked by cutie pie! 3 in Science & Mathematics ➔ Mathematics
There are 2^8 = 256 possible sequences of heads and tails. Of these, 8!/(2! 6!) = 28 contain exactly 6 heads and 2 tails. The probability is 28/256 = 7/64.
8!/(1! 7!) = 8 sequences contain exactly 7 heads and 1 tail. The probability of this outcome is 8/256 = 1/32.
2007-05-13 12:32:40 · answer #1 · answered by wild_turkey_willie 5 · 0⤊ 0⤋
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1
1 8 28 56 70 56 28 8 1
Probability of tossing exactly 6h,2t = 28/256 = 7/64
Probability of tossing exactly 7h,1t = 8/256 = 1/32
2007-05-13 12:26:34 · answer #2 · answered by Steve A 7 · 1⤊ 0⤋
Tails!
2007-05-13 12:22:08 · answer #3 · answered by Heads up! 5 · 0⤊ 1⤋