Why does Josh Beckett always get injured?
2007-05-13 10:08:18 · 9 answers · asked by Anonymous in Sports ➔ Baseball
Dont worry or panic, it is minor, it is just a tear of the skin much better then a blister, he will miss one start that is it
2007-05-17 06:23:30 · answer #1 · answered by Chris 6 · 0⤊ 1⤋
What do you mean? He doesn't always get injured. He made all of his starts last year and this is just a little skin that's torn over his finger. He'll bounce back in no time!!
2007-05-14 10:17:45 · answer #2 · answered by beckett's girl 3 · 0⤊ 0⤋
He's injury prone. Namely that blister problem that kept recurring when he was with the Marlins. The guy is having an amazing season lets just hope its not that serious and he can continue his Cy Young caliber season.
If this injury isn't serious and he can stay healthy for the entire season, I think he can win 20.
2007-05-13 17:33:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
He'll be ok. It wasn't a muscle tear or anythin serious this time. He'll be ready for his next start and they will monitor this closely to make sure it doesn't keep coming back. If the season ended today he would be the runaway Cy Young winner...so don't panic.
2007-05-13 17:26:34 · answer #4 · answered by ajn4664_ksu 4 · 0⤊ 1⤋
it's a blister on his middle finger, a ton of pitchers get this because of the way they throw the ball for different pitches. I wouldn't be worried about it.
2007-05-13 17:22:51 · answer #5 · answered by etnieskid97 2 · 0⤊ 0⤋
I'm sure that his finger will be fine and also he won't get the loss since the sox are rallying.
2007-05-13 17:18:59 · answer #6 · answered by Anonymous · 0⤊ 0⤋
doesn't take care of himself. look at how he throws all those fastballs a sure case to get injured every year. He throws fastballs like Kerry Wood.
2007-05-13 18:37:15 · answer #7 · answered by Dodgerblue 5 · 1⤊ 2⤋
don't panic. it is a finger injury and the Sox will deal with it....
2007-05-14 13:53:07 · answer #8 · answered by Jim G 7 · 0⤊ 0⤋
Dodgersblower is an idiot.
2007-05-13 22:35:44 · answer #9 · answered by ronald g 5 · 0⤊ 0⤋