2/3x + y = 0
2/3x - y = 8
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whats the easiest way to do this?
2007-05-13 09:30:17 · 5 answers · asked by grem 3 in Science & Mathematics ➔ Mathematics
Step 1) Add the two equations so that the y cancels out therefore leaving it to solve for x: (2/3x+y=0)+(2/3x-y=8)
Step 2) Solve for x: 3/4(4/3=8)
Step 3) Substitute x=6 into either equation (I put it into first) therefore solving for y: 2/3(6)+y=0 4+y=0
Step 4) Solve for y: y=-4
Step 5) Write answer in (x,y): (6,-4)
P.S. (Toward person who said no solution) I proved there was a solution to this equation.
2007-05-13 09:42:08 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Do you notice that one equation has +y and the other -y?
That's a clue that elimination is the best method.
Add the 2 equations to get
(4/3)*x = 8
So x = 6
Substitute this back in any of the equations to get
y = -4
2007-05-13 16:38:32 · answer #2 · answered by Dr D 7 · 1⤊ 0⤋
solve both of them simultaneously
2/3x + y = 0
2/3x - y = 8
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4/3x=8 (by adding both eq)
x=6
now plug it in any one
2/3*6+y=0
y=-4
therefore ans is x=6, y=-4
2007-05-13 16:39:40 · answer #3 · answered by Anonymous · 1⤊ 0⤋
ADD:-
(4/3).x = 8
x = 24 / 4
x = 6
4 + y = 0
y = - 4
Solution is x = 6 , y = - 4
2007-05-13 16:42:04 · answer #4 · answered by Como 7 · 1⤊ 0⤋
this is a no solution ,equation you twit
2007-05-13 16:34:16 · answer #5 · answered by mishman 1 · 0⤊ 2⤋