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Solve these simultaneous equations:

2d + 3c = 1.51
4d + 10c = 4.02

Thank you!

2007-05-13 09:07:08 · 3 answers · asked by wankerfromacrosstheroad 2 in Science & Mathematics Mathematics

3 answers

- 4d - 6c = - 3.02
4d + 10c = 4.02----ADD
4c = 1
c = 1/4 or 0.25

2d + 3/4 = 1.51
2d = 1.51 - 0.75
2d = 0.76
d = 0.38

c = 0.25 , d = 0.38

2007-05-13 09:25:38 · answer #1 · answered by Como 7 · 0 0

2d+3c=1.51---equ1
4d+10c=4.02---equ2
swap the coefficient of d between that below and above.you then have the followin equation.
8d+12c=6.04
8d+20c=8.04 introduce negative sign.the equation is now-8c=-2 c=1/4.substi c in2 equ-1 2d+3[1/4]=1.51
collect like terms.there4,d=0.38

2007-05-13 10:35:35 · answer #2 · answered by Taiwolee 1 · 0 0

c=0.25
d=0.38

2007-05-13 09:13:32 · answer #3 · answered by laughriot 1 · 0 0

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