also what is 5 in the binary system???
2007-05-13 08:26:55 · 5 answers · asked by heythere 2 in Science & Mathematics ➔ Mathematics
The answer to the first question is 9:
1001 base 2 = 1*2^3 + 0*2^2 + 0*2^1 + 1*2^0
1001 base 2 = 1*8 + 0*4 + 0*2 + 1*1
1001 base 2 = 8 + 0 + 0 + 1
1001 base 2 = 9
Answer to the second question is 101
5 base 10 in base 2 = 1 four, no twos, and 1 one
5 base 10 in base 2 = 1*2^2 + 0*2^1 + 1*2^0
5 base 10 in base 2 = 101
2007-05-13 08:28:49 · answer #1 · answered by McFate 7 · 1⤊ 0⤋
in binary, the first digit is 2^0, second digit is 2^1, third digit is 2^2,etc. So 1001 = 1*2^3 + 1*2^0 = 8+1 = 9 in base 10.
5(base10) in binary would need one 4 and one 1, so it's 1*2^2 + 1*2^0 = 101.
2007-05-13 10:48:10 · answer #2 · answered by Kathleen K 7 · 0⤊ 0⤋
The binary number is 1*2³ + 0*2² + 0*2 + 1 = 9.
5 in binary is 101.
2007-05-13 09:32:46 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
9
2007-05-13 08:32:12 · answer #4 · answered by gjmb1960 7 · 0⤊ 0⤋
Nine. Binary means base two, and 1001 in binary means 1x2^3 + 0x2*2 + 0x2^1 + 1x2*0. Eight plus one is nine.
2007-05-13 08:30:52 · answer #5 · answered by Anonymous · 0⤊ 0⤋