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2007-05-13 07:12:51 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

2y - 5 + 3y = 4 - (y + 2)

5y - 5 = 4 - y - 2

5y - 5 = 2 - y

5y - 5 + y = 2 - y + y

6y - 5 = 2

6y - 5 + 5 = 2 + 5

6y = 7

6y / 6 = 7 / 6

y = 7 / 6

y = 1 1/6

- - - - - - - - - - - -s-

2007-05-13 07:52:10 · answer #1 · answered by SAMUEL D 7 · 1 0

2y - 5 + 3y = 4 - (y+2)

First, factor the negative sign.
2y - 5 + 3y = 4 - y - 2

Second, combine like terms on both sides of the equation.
5y - 5 = 2 - y

Next, move all variable terms to one side of the equation, and all other terms to the other side of the equation.
6y = 7

Finally, isolate the variable by dividing each side y the coefficient (in this case, the 2 in front of the y)
y = 7/6

To check your answer, substitute this number into the original equation:
2(7/6) - 5 + 3(7/6) = 4 - (7/6 + 2)
14/6 - 30/6 + 21/6 = 4 - (7/6 + 12/6)
5/6 = 24/6 - 19/6
5/6 = 5/6

Hope this helps!

2007-05-13 07:37:11 · answer #2 · answered by allstargurl522 3 · 0 1

Solve the "y" variable in the equation.

2y - 5 + 3y = 4 - (y+2)
2y + 3y - 5 = 4 - y - 2
5y - 5 = 2 - y

First: add "y" to both sides (when you move a term to the opposite side).

5y - 5 + y = 2 - y + y
5y + y - 5 = 2
6y - 5 = 2

Sec: add 5 to both sides.

6y - 5 + 5 = 2 + 5
6y = 2 + 5
6y = 7

Third: divide both sides by 6.

6y/6 = 7/6
y = 7/6

2007-05-13 07:21:44 · answer #3 · answered by ♪♥Annie♥♪ 6 · 1 1

permit's try: 40 5-[4-2y-4(y+7)]= -4(a million+3y)-[4-3(y+2)-2(2y-5)] dispensing: 40 5-[4-2y-4y-28)] = -4-12y -[4-3y - 6 - 4y +10] 40 5-4+2y+4y+28 = -4 - 12y -4 +3y +6 +4y-10 sixty 9 + 6y = -5y -12 11y = -sixty 9-12 11y = -80 one it truly is nevertheless a fragment,,hmm..too undesirable.. y = -80 one/eleven

2016-12-17 11:35:04 · answer #4 · answered by Anonymous · 0 0

2y - 5 + 3y = 4 - (y + 2)

2y - 5 + 3y = 4 - y - 2
(distribute the - sign)
5y - 5 = 4 - y - 2
(add the two y terms on the left)
5y - 5 = 2 - y
(add the two constant terms on the right)
6y - 5 = 2
(add y to both sides, in order to get rid of y terms on the left)
6y = 7
(add 5 to both sides, in order to get rid of constant terms on the right)
y = 7/6 = 1.16666...
(divide)

2007-05-13 07:23:38 · answer #5 · answered by cantorset 2 · 0 1

first of all simplify this equation by adding the y's and the simple numbers:

5y-5 = 4 - y -2

5y-5 = 2 -y

now get the y in the right side and put it in the left side dont forget that their signs change when they get from one side to the other.

5y + y = 5 +2

6y = 7

y =7/6

2007-05-13 07:28:15 · answer #6 · answered by kamil n 1 · 0 1

basically, shift all the coefficients of y to one side, and the rest to the other side so you get

2y +3y + y = 4 +5 -2
so you get 6y = 7
then y = 7/6

2007-05-13 07:29:12 · answer #7 · answered by Anonymous · 0 1

y=13

2007-05-13 07:19:38 · answer #8 · answered by someone 2 · 0 3

Shankar is right, its 7/6 (or 1 1/6)

2007-05-13 07:24:48 · answer #9 · answered by magnificientred 2 · 0 1

it simplifies to 6y=7
or y = 7/6

2007-05-13 07:16:21 · answer #10 · answered by shankar 2 · 0 2

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