The unit Ksp for Ag3(PO4) is?

Question

1. ML-1
2. M2L-2
3. M3L-3
4. M4L-4

Answer 1

The solubility product for Ag3(PO4) can be given as:

Ksp = (Ag)^3*(PO4);
and concentration of ions is given in terms of moles/litre;

Therefore unit of Ksp should be :

( ML^-1)^3* (ML^-1)

or ( M^3 L^-3) (ML^-1)

or ( M^4.L^-4)

Hence, option '4" is correct.

Answer 2

Actually, Ksp values do not have units. You are supposed to start with concentrations in molarity and then divide all concentrations by 1M before putting them into the Ksp equation. This means all the units would cancel out and Ksp has no units. Most people skip this step because you are only dividing by 1 so it does not change the final answer. So, none of the choices are correct.

Answer 3

Answer 4.