The Ksp of CuS,Ag2S and HgS are 10-31,10-44 and 1o-54 respectively. The solubility of these sulphides in water shows the order
1. Ag2S>CuS>hgS
2. Ag2S>HgS>CuS
3. HgS>Ag2S>CuS
4. CuS>Ag2S>hgS
2007-05-11 18:59:03 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The trick here is to take the cube root of Ag2S, and compare it to the square root of the others.
Answer 1 is correct.
2007-05-11 19:53:40 · answer #1 · answered by Gervald F 7 · 1⤊ 0⤋
Solubility of CuS :
(10^-31)^1/2 = ( 10^-31/2);
Ag2S :
(10^-44)^1/3 =( 10^-44/3);
HgS ;
(10^-54)^1/2 = (10^ -54/2) =(10^-27);
The order of solubility will be as per above values:
Hence ,the order of solubility is:
Ag2S> CuS > HgS
Option '1' is correct.
2007-05-12 00:05:42 · answer #2 · answered by sb 7 · 2⤊ 0⤋
Cus Solubility
2016-12-18 07:35:08 · answer #3 · answered by llerena 4 · 0⤊ 0⤋