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I have a math problem that states square root of 6 plus square root of 6. How do you add two square roots?

2007-05-11 16:34:50 · 7 answers · asked by Demonix 1 in Science & Mathematics Mathematics

7 answers

The answer would be 2 times the square root of six, because you're adding the same number to itself.

2007-05-11 16:37:16 · answer #1 · answered by peteryoung144 6 · 2 0

Treat the square roots as x because they are both the same. The answer would be 2 square root 6.

2007-05-11 16:39:13 · answer #2 · answered by Anonymous · 0 0

if the number inside the radical signs are the same, just add them, like on ur example the answer is 2 sq. root of 6, but if the numbers are different simplify the numbers inside the radical sign else just put the plus sign between them.

2007-05-11 16:43:41 · answer #3 · answered by Christian adroits 1 · 0 0

You can do it so long as the roots are the same. The answer to this is 2*sqrt(6).

Hint: if they give you something like sqrt(3) + sqrt(6) then make sqrt(6) = sqrt(2)*sqrt(3) and adding them get (1 + sqrt(2)) * sqrt(3)

2007-05-11 16:38:00 · answer #4 · answered by TychaBrahe 7 · 1 1

are you asking sq. root of (2 plus the sq. root of (2)) or sq. root of (2) PLUS the sq. root of (2) for the 2d, the respond is two * sq. roots of two; 2(2^(a million/2)) so; 2^(3/2) that's the appropriate answer.

2016-10-15 10:39:00 · answer #5 · answered by Anonymous · 0 0

All of the above are correct, but i just wanna add in something.

You cant get a single real number when you add sq rts of non-squarable together because they are irrational numbers. you cannot have exact solutions.

2007-05-11 17:12:21 · answer #6 · answered by phoenixthe1st 2 · 0 0

6 sq rt + 6 sq rt = 2(6 sq rt). u treat it like a literal term, like in algebra. eg, x= 6 sq rt. x+x=2x.

2007-05-11 16:39:30 · answer #7 · answered by FeCl3 2 · 0 0

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