What is the mass in grams of the following?
6.043 10^23 atoms Ag
I said 106.7g but the answer isn't that. Is the answer wrong or me??
2007-05-11 16:27:45 · 5 answers · asked by bebostep 2 in Science & Mathematics ➔ Chemistry
107.9(6.043*10^23)/(6.022*10^23) = 108.28 g
2007-05-11 16:39:52 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
6.043 10^23 atoms Ag = 1 mol of Ag
1 mol Ag = 107.87g
2007-05-11 23:38:33 · answer #2 · answered by Josh 3 · 0⤊ 0⤋
Divide 6.043 x 10^23 by 6.02 x 10^23.
then multiply your answer by the molar mass of silver, 107.87
2007-05-11 23:35:41 · answer #3 · answered by peteryoung144 6 · 0⤊ 0⤋
1 mole is a amount of substance that contains 6.02*10^23 molecules or atoms of that element or compound.so 6.02*10^23 atoms oh Ag is equal to the i mole of Ag and one mole of Ag is equal to107.87 g which is equal to the atomic mass of Ag
2007-05-11 23:35:34 · answer #4 · answered by rana h 2 · 0⤊ 0⤋
wronge!! thts so easy!!
2007-05-11 23:30:05 · answer #5 · answered by ? Electric Emiily ? 4 · 0⤊ 0⤋