Math problem? :/?

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To the nearest tenth, find the length of a side of a square whose area is equal to the area of a triangle with an altitude of 18 cm and a base of 11 cm.

2007-05-11 15:45:49 · 3 answers · asked by Lizzie 5 in Science & Mathematics ➔ Mathematics

3 answers

area of the triangle is 1/2 base * height = .5 * 18cm * 11 cm = 99 cm^2

the area of a square is side^2 = 99 cm^2 = sqrt(99) cm is the length of the side.

2007-05-11 15:48:42 · answer #1 · answered by metalluka 3 · 0⤊ 0⤋

Area of triangle = 1/2 x 11 x 18 cm²
Area of triangle = 99 cm² = Area of square
Length of side of square = √99 cm = 9.9 cm

2007-05-12 04:38:55 · answer #2 · answered by Como 7 · 0⤊ 0⤋

s=9.9 cm

2007-05-11 15:52:27 · answer #3 · answered by Quasi 1 · 0⤊ 0⤋