a package of compounds used to achieve rehydration in sick patients contains 21.0 g of glucose, C6H12O6....?

Question

a package of compounds used to achieve rehydration in sick patients contains 21.0 g of glucose, C6H12O6. When this material is diluted to 1.18 L, what is the molarity of glucose?

Answer 1

C6H12O6=180 g per mole
21g/180g=0.12 moles
divided by 1.18L
=0.099 M

Answer 2

Add up the atoms in glucose to get the molecular mass.

Divide 21.0 grams by this number to get moles of glucose.

Now divide by 1.18 L to get molarity