2007-05-11 11:01:31 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Do you mean: (3/x+5) / y
First: make the "y" variable a fraction - place "y" over 1.
(3/x+5) / (y/1)
Sec: rule - you can't divide fractions; multiply the 1st fraction with the reciprocal of the 2nd fraction (flip the 2nd fraction).
(3/x+5) * (1/y)
Third: combine the fractions.
(3*1)/(x+5)(y)
= 3/(x+5)(y)
2007-05-11 11:13:29 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
15+x over Y
2007-05-11 11:46:16 · answer #2 · answered by Anonymous · 0⤊ 0⤋
3/(x+5)/y = 3/(x+5) * 1/y = 3/y(x+5)
2007-05-11 11:10:33 · answer #3 · answered by danjlil_43515 4 · 0⤊ 1⤋
first, you have to find the common demominator which is xy. Then, you have to multiply the 3 by y 'cuz it doesn't have a y and the 5 by the x. so the answer is 3y + 5x over xy.
2007-05-11 11:07:57 · answer #4 · answered by soph3gurl 3 · 0⤊ 1⤋
Do you mean (3/x) + (5/y), or 3 / (x + (5/y)), or 3 / ((x+5)/y)? I'll just assume you mean the first one.
3/x + 5/y is already in its simplest terms, but if you wanted to combine the fractions you could give them a common denominator and add:
3y/xy + 5x/xy
(3y + 5x) / xy
2007-05-11 11:07:10 · answer #5 · answered by Anonymous · 1⤊ 1⤋
if u mean 3/(x+5)/y:
multiply (x+5)/y by its reciprocal, then multiply the reciprocal by three to get: 3y / (x+5).
2007-05-11 11:11:46 · answer #6 · answered by Anonymous · 0⤊ 1⤋
3/x + 5/y is already in simplest form
2007-05-11 11:06:08 · answer #7 · answered by shanusav 2 · 0⤊ 1⤋
3/x + 5/y = 3y/xy + 5x/xy
= (3y + 5x )/xy
2007-05-11 11:32:06 · answer #8 · answered by muhamed a 4 · 0⤊ 0⤋
3/x+5/y
the LCD is xy
3y +5x
---------
xy
2007-05-11 12:51:34 · answer #9 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(3y+5x)/xy
2007-05-11 11:07:14 · answer #10 · answered by bruinfan 7 · 0⤊ 0⤋