Derivate this time..!?

0 ⤊

How to derivate this...

0,5e^(-x^2)

Thanks..;)

2007-05-11 08:05:56 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

-xe^(-x^2)
------------
Reason:
Used chain rule.
[0,5e^(-x^2)]'
= 0,5e^(-x^2)(-2x)

2007-05-11 08:10:14 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋

1/2* (-2x)* e^(-x^2)

or

-x e^(-x^2)

2007-05-11 15:09:59 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋

Let u(x)=-x^2

d[e^u(x)]/dx = e^u(x) du(x)/dx

Since du(x)/dx = -2x

d[0.5e^(-x^2)]/dx = 0.5(-2x)e^(-x^2) = -xe^(-x^2)

2007-05-11 15:11:31 · answer #3 · answered by Astral Walker 7 · 0⤊ 0⤋

chain rule

y = 0.5e^(-x^2)

dy/dx = 0.5 (-2x) e^(-x^2)

......... = -xe^(-x^2)

2007-05-11 15:11:00 · answer #4 · answered by fred 5 · 0⤊ 0⤋