2007-05-11 07:09:39 · 12 answers · asked by bharat m 3 in Science & Mathematics ➔ Mathematics
here 3x+15>5x+5
=>15-5>5x-3x
=>10>2x
=> 5>x [divide by 5=/=0]
since x is a natural number ,hence possible values of x are 1,2,3,4.
2007-05-11 07:17:17 · answer #1 · answered by chapani himanshu v 2 · 0⤊ 2⤋
Goal - isolate the "x" variable on one side.
First: subtract 5x from both sides (when you move a term to the opposite side, always use the opposite sign).
3x - 5x + 15 > 5x - 5x + 5
3x - 5x + 15 > 5
- 2x + 15 > 5
Sec: subtract 15 from both sides.
- 2x + 15 - 15 > 5 - 15
- 2x > 5 - 15
- 2x > - 10
Third: divide both sides by -2 (when you divide by a negative number within an inequality, reverse the sign).
- 2x/-2 > - 10/-2
x < -10/-2
x < 5
2007-05-11 14:38:43 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
3x + 15 > 5x + 5
3x-5x>5-15
-2x>-10
-x>-10/2
-x>-5 because x is negative, so you switch sign to <
x<5
2007-05-11 14:16:30 · answer #3 · answered by ۞_ʞɾ_ 6 · 0⤊ 0⤋
3x + 15 > 5x + 5
3x - 5x > 5 - 15
-2x > -10
x < -10/-2
x < 5
Solution: {x belongs to N | x < 5}
>:>
2007-05-11 14:25:43 · answer #4 · answered by aeiou 7 · 0⤊ 0⤋
3x + 15 > 5x + 5
15 - 5 > 5x - 3x
10 > 2x
5 > x
2007-05-11 14:14:44 · answer #5 · answered by clemsonu79 1 · 0⤊ 2⤋
x=4
2007-05-11 14:13:56 · answer #6 · answered by sarah b 1 · 0⤊ 2⤋
3x+15>5x+5
15-5>5x-3x
10 > 2x
x<5
x is smaller than 5. :-)
2007-05-11 14:15:15 · answer #7 · answered by Raj 2 · 0⤊ 0⤋
3x + 15 > 5x + 5
15 -5 > 5x -3x
10 > 2x
5 > x
Done.
2007-05-11 14:14:30 · answer #8 · answered by Jerry P 6 · 0⤊ 2⤋
3x+15>5x+5
15-5>5x-3x
10>2x
10/2>x
5>x
2007-05-12 02:01:15 · answer #9 · answered by sam 3 · 0⤊ 0⤋
3x+15>5x+5
3x-3x+15>5x-3x+5
15>2x+5
15-5>2x+5-5
10>2x
5>x
2007-05-11 14:16:03 · answer #10 · answered by Dave aka Spider Monkey 7 · 0⤊ 2⤋