1. distributive property
x + 15x -100 = 10x - 40
2. add common variables
16x - 100 = 10x - 40
3. add 100 to each side
16x = 10x + 60
4. subtract 10x from each side
6x = 60
5. divide each side by 6
x = 10
2007-05-11 06:31:23
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answer #1
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answered by Bethany 2
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Solve the "x" variable in the equation.
x + 5(3x - 20) = 10(x - 4)
First: eliminate parenthesis - use the distribution method.
x+5(3x)+5(-20) = 10(x)+10(-4)
x+15x-100= 10x-40
16x - 100 = 10x - 40
Sec: subtract 10x from both sides (when you move a term to the opposit side, always use the opposite sign).
16x - 10x - 100 = 10x- 10x - 40
6x - 100 = - 40
Sec: add 100 with both sides.
6x - 100 +100= - 40 + 100
6x = 60
Third: divide both sides by 6.
6x/6 = 60/6
x = 10
2007-05-11 12:53:39
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answer #2
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answered by ♪♥Annie♥♪ 6
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Simplifying one part at a time...
x + 5(3x-20) = 10(x-4)
x + 15X - 100 = 10x - 40
16x - 100 = 10x - 40
6x - 100 = -40
6x = 60
x = 10
2007-05-11 06:29:05
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answer #3
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answered by jonmm 4
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=> x + 15x -100 = 10x -40
=> 16x -100 = 10x -40
=> 16x - 10x = -40 + 100
=> 6x = 60
=> x = 10
2007-05-11 21:32:41
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answer #4
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answered by ♫})i({ ♥∂Λ₱ħѝε♥ })i({♫ 4
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Follow the order of operations.
x + 15x - 100 = 10x - 40
Collect like terms:
16x - 10x = 100 - 40
6x = 60
x = 10.
2007-05-11 06:33:24
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answer #5
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answered by Anonymous
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x + 15x - 100 = 10x - 40
16x - 10x = 100 - 40
6x = 60
x = 10
2007-05-11 21:07:57
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answer #6
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answered by Como 7
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I think its this, hope that helps
x+5(3x-20)=10(x-4)
x+15x-100=10x-40
-10x -10x
x+5x-100=-40
+100 +100
x+5x=60
6x=60
x=10
2007-05-11 06:34:09
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answer #7
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answered by Ashley 1
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we can solve this using trial and error, letme for the sake of ease take x=5, then
5+ 5(3*5-20)
5+5(15-20)
nah not right
lets try 10
10+ 5(3*10-20)
10+ 5(10)
10+50
60
=10(10-4)
=60
voila
2007-05-11 06:36:06
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answer #8
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answered by Gooner44 2
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x+5(3x-20)=10(x-4)
x+15x-100=10x-40
16x-100=10x-40
16x-10x=-40+100
6x=60
x=60/6
x=10
2007-05-11 18:48:11
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answer #9
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answered by sam 3
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