A gas occupies 11.2L at 0.860atm . What is the pressure if the volume becomes 150L?
please show work and gas law used
i got 0.064atms but i think it is wrong...
2007-05-11 03:47:05 · 3 answers · asked by Riley 1 in Science & Mathematics ➔ Chemistry
well it has to be a much lower number so 1st 11.2/150=.07466666 then multiply .860 by .07466666=.0642 so you are right.
2007-05-11 03:51:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You have pV=nRT
If the temperature is constant, and you compare conditions 1 to conditions 2
p1V1= p2V2
so p2 =p1V1/V2 here V1 =11.2L, p1= 0.86 atm , V2 = 150L
p2 = 11.2*0.86/150= 0.0642atm
You were right!
2007-05-11 10:55:44 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
Boyle's Law
P1V1 = P2V2
(.860)(11.2) = P2(150)
[(.860)(11.2)]/150 = P2
P2 = .064 atm
2007-05-11 10:54:19 · answer #3 · answered by xconstantescapex 1 · 0⤊ 0⤋