A sample of gas occupies 1.55 L at 27oC and 1.00 atm pressure. What will the volume be if the pressure is increased to 50.0 atm, but the temperature is kept constant?
2007-05-11 03:25:33 · 4 answers · asked by j_3_s_5 1 in Science & Mathematics ➔ Chemistry
PV = T
With temperature constant,
PV = constant
1.55 L * 1.00 atm = V * 50 atm
1.55 L / 50 = V = 31 milliliters
2007-05-11 03:31:27 · answer #1 · answered by DanE 7 · 0⤊ 0⤋
Just use the formula PV=nRT P is pyour pressure, V is your volume, n is the # of moles which can be assumed in your problem to be 1, R is the gas constant .0821, and T is your temperature or kelvin, just add 27 degrees celsius to 273 kelvin and then just do the math from there. If the pressure is increased to 50 ATM then just put 50 ATM in for the Pressure. Then just do the math out that is your answer, which is .031 liters btw.
2007-05-11 03:30:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
PV = RT and since R is a constant, and T is kept constant, PV has to be a constant,
P1 V1 = P2 V2 or V2 = P1 V1/P2 = 1 X 1.55 / 50 = 0.031 litres
2007-05-11 03:30:18 · answer #3 · answered by Swamy 7 · 1⤊ 0⤋
Since the temp is constant;
apply
P1V1 = P2V2
1*1.55 = 50* V2
V2=0.031L
2007-05-11 04:55:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋