If f(x) = u/v, what is the derivative of f(x)?
a) f’(x) = u’v + uv’/v
b) f’(x) = u’v – uv’/v
c) f’(x) = u’v + uv’/v^2
d) f’(x) = u’v – uv’/v^2
2007-05-11 03:11:13 · 10 answers · asked by Full of Questions 1 in Science & Mathematics ➔ Mathematics
Actually the way the problem is stated, I vote for none of the above.
f’(x) = (u’v – uv’) / v^2 would be correct.
2007-05-11 03:18:42 · answer #1 · answered by fcas80 7 · 0⤊ 0⤋
D
This is the rule for finding the derivative of a quotient.
2007-05-11 03:53:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
This is the quotient rule:-
f ` (x) = ( v du/dx - u dv/dx ) / v²
Answer d) is meant to be this but brackets have been missed-----it is WHOLE of top line that is divided by v².
2007-05-11 22:31:52 · answer #3 · answered by Como 7 · 0⤊ 0⤋
you get the derivative in function of x but there is not x in f(x) so f'(x) = 0
2007-05-11 03:34:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Look at your quotient rule for derivatives, that's all it's asking.
2007-05-11 03:30:12 · answer #5 · answered by Kathleen K 7 · 0⤊ 0⤋
f(x) = 2x^3 - x^2 + 3x f'(x') = 6x^2 - 2x + 3 h(x) = (2x^2 - 3x + a million)/x i(x) = 2x^2 - 3x + a million i'(x') = 4x - 3 j(x) = x j'(x') = a million h'(x') = (x(4x - 3) - 2x^2 - 3x + a million)/(x^2) h'(x') = (4x^2 - 3x - 2x^2 - 3x + a million)/(x^2) h'(x') = (2x^2 - 6x + a million)/(x^2)
2016-11-27 02:44:53 · answer #6 · answered by keetan 4 · 0⤊ 0⤋
D. There's a mnemonics actually.
It goes: (Low)(dHigh) - (High)(dLow) all over Low squared.
2007-05-11 03:18:47 · answer #7 · answered by kpgkn29 2 · 0⤊ 0⤋
c
2007-05-11 03:16:09 · answer #8 · answered by Gene 7 · 0⤊ 0⤋
d
2007-05-11 03:15:30 · answer #9 · answered by maussy 7 · 0⤊ 0⤋
d.
2007-05-11 03:14:14 · answer #10 · answered by rrabbit 4 · 0⤊ 0⤋