Calculate the pH of a colution that is 0.41M in HOCL and 0.50M in NaOCL. Ka(HOCL)=3.2X10^-8?

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2007-05-11 03:11:04 · 2 answers · asked by justcallmejayboi 1 in Science & Mathematics ➔ Chemistry

HOCL<==>ClO- + H+

pH=pKa+[ClO-]/[HOCl]

[ClO-]approximately=0.5M
[HOCl]approximately=0.41M

pH=7.49+log(0.5/0.41)
pH=7.49+0.086
pH=7.58

2007-05-11 05:01:03 · answer #1 · answered by Anonymous · 0⤊ 0⤋

pH = pK + log( [NaOCl]/[HOCl]

pK = log 1/Ka =7.49

pH = 7.49 +log 0.5/0.41 =0.086+7.49= 7.58

2007-05-11 03:22:06 · answer #2 · answered by maussy 7 · 0⤊ 0⤋