2007-05-09 22:05:41 · 3 answers · asked by clock 2 in Science & Mathematics ➔ Mathematics
Substitute z = 2 into sphere equation to find where they meet
x^2 + y^2 +4 - 2x - 4y -12 + 5 = 0 which is a circle
x^2 - 2x + y^2 -4y -3 = 0
complete the square for the x terms and then the y terms
(x - 1)^2 -1 + (y - 2)^2 - 4 -3 = 0
(x - 1)^2 + (y - 2)^2 = 8
radius is √8 or 2√ 2
2007-05-09 22:19:08 · answer #1 · answered by fred 5 · 1⤊ 0⤋
Regroup the variables:
x^2 - 2x + y^2 - 4y + z^2 - 6z = - 5
Find the center and radius of the sphere by completing the squares.
x^2 - 2x + 1 + y^2 - 4y + 4 + z^2 - 6z + 9 = - 5 + 1 + 4 + 9
(x - 1)^2 + (y - 2)^2 + (z - 3)^2 = 9
center at (1,2,3), R = 3
The plane intersects the sphere 1 unit below the center:
r = â(9 - 1) = â8 = 2â2
2007-05-10 05:25:27 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
CALL OUTERSPACE U R OUT THERE AWAY FROM NORMALITY
2007-05-10 05:08:58 · answer #3 · answered by ttkmb 2 · 0⤊ 2⤋