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A toyota sienna with a gross weight of 5300 lbs is parked on a street with slope of 8 degrees. Find the force required to keep Sienna from rolling down the hill ? . What is the force perpendicular to the hill?

2007-05-09 18:26:57 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

F = Downhill force = 5300 x sin 8°
F = 737.6 lbs = Required uphill force to prevent rolling down the hill.
Perpendicular force = 5300 cos 8°
= 5248.4 lbs.

2007-05-09 19:52:43 · answer #1 · answered by Como 7 · 0 0

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