Find the center of the equation 2x^2+2y^2+10x-5=0. it's a circle?

Question

i got the answer ,but if anyone wants to answer for that 5 pts go right ahead

Answer 1

Complete the square to find center.
(x-h)^2 + (y-k)^2 = r^2 for center (h,k)

Divide by 2 to make life easy

x^2 + y^2 + 5x = 5/2
x^2 + 5x + ____+y^2 = 5/2 + _____

x^2 + 5x + 25/4+y^2 = 5/2 + 25/4
(x+5/2)^2 + y^2 = 35/4

CENTER (-5/2 , 0)

=]

Answer 2

x² + y² + 5x - 5/2 = 0
(x² + 5x)+ y² = 5/2
(x² + 5x + 25/4) + (y - 0)² = 5/2 + 25/4
(x + 5/2)² + y² = 35/4
(x - (-5/2))² + (y - 0)² = 35/4
Centre ((-5/2),0)
Radius = √35/2