an airplane is flying 300km/h in a direction of 287 degrees.?

Question

Find the westerly northerly components of its velocity.

Answer 1

Use a standard graph. Let one axis represent north and south and the other axis east and west. Make sure north is at the top on one axis and that west is on the left side and east is on the right side of the other axis. Due or complete west is 270 degrees. Use a protractor and draw a line from the center of the graph and connect it to +17 degrees on the protractor. The +17 degrees above 270 degrees will represent 287 degrees. The resulting line is the plane's course. Use each square on the graph to represent distance, say 10 km. Use the slope formula to determine the plane's northerly and westerly components of the velocity. Hope you can visualize this and it makes sense.

Answer 2

Hello,

This means that the airplane is 17 degrees nnorth of west.

Draw your right triangle and let n be the side opposite the 17 degree angle and w be the side adjacent to the 17 degree angle and then 300 is the hypotenuse.

Now to find n we use sin(17) = n/300 or 300* sin(17) = 87.71 km/h

and to find w we use cos(17) = w/300 or 300*cos17 = w so
w = 286.89 km/h

Hope This Helps!!

Answer 3

Is that magnetic north or true north, 287 degrees is a NW heading, and it is going 300km/h.
270 is true west and 0 is true north, so I am not sure what you are asking exactly. To figure out true air speed we would need to no the winds aloft and to figure out the actual direction we would need to subtract or add the magnetic variance.