find the magnitude of the vector (-7,2)?

Answer 1

for a vector
magnitude of = sqrt [ a^2 + b^2 ]

I <-7 , 2> I = sqrt[ (-7)^2 + 2^2 ] = sqrt[ 49+4]
= sqrt53

that is simplified

Answer 2

Magnitude = √(7²+2²) = √53.
The general rule is to use the Pythagorean theorem
on the components.

Answer 3

Magnitude is the square root of the sum of the components squared.

(x, y)

|x, y| <---- magnitude = root(x^2 + y^2)

|-7, 2| = root(49 + 4) = root(53)

Answer 4

Let r be given vector.
| r | = √(49 + 4)
| r | = √53
| r | = 7.28