Please help with this math problem.?

Question

Here is my math problem: The length of a rectangular fenced area is 10 feet longer than its width. The area is 75 square feet. What are the dimensions of the fenced area? Explain how you got your answer please.

Answer 1

Well, we just set it up as such.

If the length is 10 feet longer than the width, then we must specify it in the formula:

l x w = A

l = 10 + w

w(10 + w) = 75

10w + w^2 = 75

w^2 + 10w = 75

w^2 + 10w - 75 = 0

Now we solve using the quadratic equation:

-10 +/- sqrt(100 - 4(-75))/(2)

-10 +/- sqrt(100 + 300))/2

-10 +/- sqrt(400)/2

(-10 +/- 20)/2

Now we solve:

-10 + 20 = 10/2 = 5

-10 - 20 = -30/2 = -15

So we can conclude that the two numbers are 5 and 15:

5 x 15 = 75

And there you go.

Answer 2

Hello Groovy Babe,

Let w = the width then
W+10 = the length

Now the area is L*W or W*(W+10) = 75

or W^2 + 10W = 75

subtract 75 from both sides and get w^2 + 10 W -75 = 0

Factor (W +5)(W-15) = 0 so

w =-15 extraneous root can't have a negative length and w = 5
works
so w = 5 and W+10 = 15 feet.

Hope This Helps
and W+10 = 25

Answer 3

The fenced area is 5 x 15. You know that the width is 'x' and the length is 'x + 10'. This may or may not be the best way to do it, but you could just guess and check to get the answer.

Answer 4

(w)(w+10)=75 w^2+10w=75 w^2 +10w -75 =0
(w+15)(w-5) = o since dimensions can't e negative w=5
so the width is 5 ft and the length is 15 ft

Answer 5

length = width + 10

area = length * width = 75

(width + 10) * width = 75 (from top)

width squared + 10 width = 75

gives you width = 5

and length = 15

Answer 6

5 by 15

guess and check numbers 10 apart that equal 75

Answer 7

If you want to your good answer, you have to explain good ???. your ??? is not properly so please aask agian. I am feeling you are new in yahoo answer, Am i right? bye friend