A house has 6 stories, each the same height. How many times as long is the ascent to the sixth floor as the ascent to the third floor.
2007-05-09 15:21:13 · 3 answers · asked by klzplaya 1 in Science & Mathematics ➔ Mathematics
I think this is a trick question: most people will think that "six is twice as much as three, so it's twice as far."
But the way floors are numbered in most places, you don't start on the zero-th floor, you start out on the first floor.
From the first floor, you'd ascend two floors to reach the third floor. Climbing one floor would place you on the second floor, and climbing one more would place you on the third .
From the first floor, you'd ascend five floors to reach the sixth floor. ((1) second floor, (2) third floor, (3) fourth floor, (4) fifth floor, (5) sixth floor.)
So, the ratio of the ascent to the sixth floor and the ascent to the third floor, is 5/2. The ascent to the sixth floor is 2.5 times as long.
2007-05-09 15:35:16 · answer #1 · answered by McFate 7 · 1⤊ 0⤋
well, the ascent to the 6th floor is twice as long as the ascent to the 3rd floor (cuz 3 times 2 is 6). So, it is 2 times longer.
2007-05-09 15:30:26 · answer #2 · answered by Anonymous · 1⤊ 1⤋
i'm not sure what the question means, but it seems they are asking you to compare the ledge of the third floor and the ledge of the sixth floor, or in other words, the top of the second floor and the top of the fifth floor
hence, two and a half times
2007-05-09 15:34:39 · answer #3 · answered by Billy 5 · 2⤊ 0⤋