do they hit the floor at the same time and have the same distance?
2007-05-09 12:42:35 · 4 answers · asked by msclassyleo 1 in Science & Mathematics ➔ Physics
They will hit at the same time without air resistance. If air is present, the more massive one will go slightly farther and hit the floor slightly sooner.
2007-05-09 12:59:34 · answer #1 · answered by Steve 7 · 0⤊ 0⤋
They have difference forces of gravity, but the same acceleration due to gravity. If there is no air friction present (like on the moon with the feather and the hammer) they will fall at the same rate since there is no other forces present.
If air resistance exists, then the shape of the object is considered. Since they are both spherical and of the same size, the air resistance is equal for both. Since the force of gravity is larger for the object with the most mass, then the force of air resistance will be a smaller component of the motion.
given g = acceleration due to gravity
m = mass of the object
r = force of air resistance
For the lighter object the acceleration =
(gm - r) / m = a
For the heavier object the acceleration =
(g2m - r) / 2m = a
A slightly larger acceleration for the heavier object.
2007-05-09 20:30:00 · answer #2 · answered by Math Guy 4 · 0⤊ 0⤋
yes they do. THey are accelerating due to gravity and gravity is does not take into acount mass.
2007-05-09 19:57:03 · answer #3 · answered by Brandon 3 · 0⤊ 0⤋
Yes that's correct
2007-05-09 19:54:44 · answer #4 · answered by Gene 7 · 0⤊ 0⤋