How would i find the equation of the line with the y-intercept of 1 that passes through the point (2,9)?

Answer 1

Here's how. The slope-intercept form of the equation for a line is y = mx + b, where m is the slope, b is the y-intercept, and x and y are the coordinates of any point on the line. You are given the coordinates of a point on the line: x = 2, y = 9, and the y-intercept: 1. All you have to do is plug these into the above equation and solve for m.

y = mx + b
9 = 2m + 1
8 = 2m
4 = m

So your equation is: y = 4x + 1.

As a check, substitute 2 for x in the last equation and see if the result is 9.

y = 4 (2) + 1
y = 9

So our answer seems to be correct.

Answer 2

y = aX + b
y ntercept = 1
y = aX + 1
st line passing through ( 2 , 9 )
9 = 2 a + 1
2a =9-1
2a=8
a=4
the equation is y = 4 X + 1