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Let's say that it is 100% factual that black holes do give off Hawking radiation. How long would it take a black hole of 10 solar masses to completely evaporate (assuming it swallowed no more matter or light for the rest of time).

2007-05-09 07:57:27 · 7 answers · asked by James M 1 in Science & Mathematics Astronomy & Space

7 answers

Actually, only black holes of mass less than that of Earth's moon, approximately, will evaporate due to Hawking radiation. Any black hole more massive is so cold (because the temperature of a black hole is inversely proportional to its mass) that it will absorb more energy from the cosmic background radiation than it emits as Hawking radiation.

2007-05-09 08:02:23 · answer #1 · answered by DavidK93 7 · 0 1

For a black hole of one solar mass (about 2×10^30 kg), we get an evaporation time of 10^67 years—much longer than the current age of the universe. But for a black hole of 10^11 kg, the evaporation time is about 3 billion years.

2007-05-09 08:06:55 · answer #2 · answered by Chug-a-Lug 7 · 1 0

I haven't looked up the actual number but I'm fairly certain that its much larger than the current age of the universe. Black hole evaporation varies inversely with black hole mass so very small black holes evaporate quickly while larger, solar mass black holes will take enormous amounts of time to evaporate. I should point out that no one understands what happens near the end of evaporation as the total disappearance of the information contained by the black hole would violate known physical laws.

2007-05-09 08:04:08 · answer #3 · answered by mistofolese 3 · 0 0

If we settle for that each and each physique debris are surrounded by a cloud of digital debris whose lifestyles is relatively short, then some exciting opportunities upward thrust up. a sturdy electric powered container will separate the surely and negatively charged debris in the time of the 2d that they exist. If separated a techniques adequate they gained't recombine and we are able to describe the form as pair creation. in addition a sturdy adequate gravitatinal container might have a similar result. in basic terms this time the particle separation relies upon upon the spontaneous momentum of the debris fairly than their cost. between the debris will descend into the form horizon and the different will take off into area. by this implies the bh slowly evaporates, the fee of evaporation being pronounced to enhance the smaller the black hollow. All it somewhat is hypothesis at contemporary as Hawking radiation has by no potential been surely stated.

2016-10-30 23:19:26 · answer #4 · answered by sherie 4 · 0 0

The time is finite, but it is so long as to be meaningless. I don't have the formula handy, but you can get an inkling from Hawking's book.

2007-05-09 08:17:33 · answer #5 · answered by Anonymous · 0 0

There are lot of complicated calculatons dude....

black holes never 'evaporate'. They get turned into black dwarfs at the last stage of life.

2007-05-09 08:04:15 · answer #6 · answered by Selena 1 · 0 5

Billions and billions of years

2007-05-09 08:13:18 · answer #7 · answered by Gene 7 · 0 0

I would guess and say um,"10,000 years" you happy now?

2007-05-09 08:03:06 · answer #8 · answered by spir_i_tual 6 · 0 2

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