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2007-05-09 04:48:08 · 4 answers · asked by smyslov2001 1 in Sports Baseball

4 answers

The formula is:

(9/number of innings pitched) X (number of earned runs allowed)

For example, a pitcher who gave up 87 earned runs in 226 innings would have it figured like this:

9 / 226 X 87 = 3.46

2007-05-09 04:51:43 · answer #1 · answered by Craig S 7 · 0 1

There are actually different ways to write the equation, but the one I use is

(ER/IP)*9=ERA

Where ER is earned runs credited to the pitcher and IP is his innings pitched. Remember that every 1 out is 1/3 of an inning pitched, so if a pitcher pitches 6 full innings and gives up 2 earned runs, his ERA is 3.00 [ (2/6)*9=3.00 ], but if he were to get 1 out in the 7th inning before being pulled without being attributed another earned run, his ERA would actually be 2.84 [ (2/6.33333)*9=2.84 ]. ERA is always to the hundreth decimal point and always rounded.

2007-05-09 12:09:40 · answer #2 · answered by Jimi L 3 · 0 1

Earned runs given up, Multiplied by 9, divided by innings pitched. For example.......If you pitch 9 innings and only give up 2 runs.......2 runs X 9= 18 divided by 9 innings= era of 2.00

2007-05-09 11:52:04 · answer #3 · answered by theroguerook 2 · 0 1

multiply the total earned runs charged against his pitching by 9, and divide the result by the total number of innings he pitched.

2007-05-09 11:51:52 · answer #4 · answered by weeder 6 · 0 1

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