sketch the graph of the polar equation- r = 2 / 1- sinx?

Answer 1

I assume you mean r = 2/(1 - sinx).

This is the equation of a parabola with focus at the origin.

r = 2/(1 - sinx)
r(1 - sinx) = 2
r - rsinx = 2
r - y = 2
r = y + 2

Square both sides.

r² = (y + 2)²
x² + y² = y² + 4y + 4
x² = 4y + 4
4y = x² - 4
y = (1/4)x² - 1

As you can see, this is the equation of a parabola with vertex (h,k) = (0,-1) that opens upwards (and the focus is at the origin).

Answer 2

Is function r=2/(1-sinx)?

If so

Have you done a table of values for r and x. For instance when x=0 sinx =0 . So r =2

So table x , sinx, 1-sinx, r. Then you will be able to draw the graph.

Also this site here. http://www.ies.co.jp/math/java/calc/sg_kyok/sg_kyok.html

Be careful to enter function as 2/(1- sin t) . You must keep space between sin and t for this to work

Answer 3

Cancel out a million,000 to grant 12(a million+r)² = 27 (a million+r)^2 = 27/12 a million+r = sqrt(27/12) = sqrt((9*3)/(4*3)) = (3sqrt3)/(2sqrt3) = 3/2 r = 0.5 (apparently r = -2.5 is likewise a answer via fact a quadratic has a plus and a minus root)

Answer 4

Make a graph of

r vs. 2/1-x

Then transfer that to a graph of y vs x, r = length of the line....