x^2 over x+6 times x^2-7x-8 over x^2 + 3x
This is the problem that really has me stuck
hepe with this would be much appreciated!
2007-05-08 22:31:09 · 5 answers · asked by Kristenite’s Back! 7 in Science & Mathematics ➔ Mathematics
just directly multiply the top part of the fraction together and the bottom part together:
1) ((x^2)((x^2-7x-8)) / ((x-6)(x^2 + 3x))
there are several other ways to write this answer:
1) (x^4-7x^3-8x^2)/(x^3+9x^2+18x)
2) ((x^2)(x-8)(x+1)) / (x(x+3)(x+6))
3) simplified version:
(x^4-7x^3-8x^2)/(x^3+9x^2+18x)
(x(x^3-7x^2-8x)) / (x(x^2+9x+18))
(x^3-7x^2-8x) / (x^2+9x+18) [the x's cancel out]
2007-05-08 22:45:02 · answer #1 · answered by Janine 1 · 1⤊ 0⤋
[ x^2 / (x+6) ] * [ (x^2-7x-8) / (x^2+3x) ]
= [ x^2 / (x+6) ] * [ (x-8)(x+1) / (x(x+3)) ]
= x^2(x-8)(x+1) / ( x(x+3)(x+6) )
= x(x-8)(x+1) / ( (x+3)(x+6) )
2007-05-09 05:57:01 · answer #2 · answered by Ben 3 · 1⤊ 0⤋
[ x^2/(x+6) ]* [(x^2-7x-8) / (x^2 + 3x)]
= [ x^2/(x+6) ]*[(x-8)(x+1) / (x(x+3))]
= (x^2)(x-8)(x+1) / (x+6)(x)(x+3)
= x(x-8)(x+1)/(x+6)(x+3)
2007-05-09 05:38:34 · answer #3 · answered by tsunamijon 4 · 1⤊ 0⤋
What is it that you are suppose to do with this expression?
Simplify? Or find the value of x?
2007-05-09 05:45:03 · answer #4 · answered by hjfhsdahfer f 1 · 1⤊ 0⤋
Nebraska. It might be a trick question.
2007-05-09 05:37:01 · answer #5 · answered by Anonymous · 0⤊ 1⤋