An Integral Problem- Kindly solve with solutions. Thank you.?

Question

A stone is thrown vertically upward from the top of a house. If it has reached its maximum height of 30 ft after 1 second. Find the height of the house- Assuming the only force acting is acceleration due to gravity (-32 ft/sec^2

Answer 1

Let x(t) be the height in feet after t seconds. Since the stone is thrown from the top of the house, x(0) is the height of the house.

x''(t) = -32
so x'(t) = -32t + c
and x(t) = -16t^2 + ct + d
Maximum is when c = 32t and this is at t = 1, so c = 32.
So x(t) = -16t^2 + 32t + d
x(1) = -16 + 32 + d = d + 16 = 30
<=> d = 14
x(0) = d = 14, so the house is 14 feet high.

Answer 2

v=u+at
v=0
a= -32ft/s^2
t= 1s

u=32ft/s

v^2=u^2+2as
0=32^2 - 2*32*s
s=(32*32)/2*32
=16 feet from the top of the house.

Height of the house = maximum height - distance from the top of the house
= 30 - 16 = 14 feet

Answer 3

i could think of.. Get the indefinite fundamental of 30x - 10 u shud have 15x^2 - 10x +c then substitute x for 5 and set the whole equation equivalent to 375. U'll see that C = 50 now plug in one thousand for x and there is ur answer. via fact marginal fee function is a by-made from the fee function .. it could make experience to apply the integrals to bypass back to the fee function.

Answer 4

hey its jus a simple formula(F=???) ....really forgot ....to get ur ans jus pos the q in yahoo india..