Math genius I need your help, Please can you help me out I am studying for a math test and I am stumped and I?

Question

don't get this and feel like a failure not just that my teacher don't like helping me:(

Simplify the following question...............................
(2x^5/8)(3x^1/8)
please explain the steps to find the answer...............Thank you

Answer 1

When bases are the same you can combine the powers in this case you use the fact that

x^a * x^b = x^a+b So now

(2x^5/8)(3x^1/8) = 2*3*x^(5/8+1/8)

= 6 x^6/8 = 6x^3/4

Answer 2

Hello tickled,

You must multiple the coefficients (numbers) and when multiplying like bases you keep the base and add the exponents so we have:

2*3*x^(5/8+1/8) or 6 x^(6/8) which reduced is 6x^(3/4)

Hope This Helps

Answer 3

(2x^5/8)(3x^1/8)
=6x^(5/8 + 1/8)
= 6x^(3/4)

As base x is same, just add the powers

Answer 4

bear in concepts that the adaptation of squares continually factors right into a manufactured from sum and ameliorations: x^2 - y^2 = (x+y)*(x-y). honestly, i think of all of those are meant to be the adaptation of squares: are you constructive the 2d isn't a^2 - 4b^2? then the climate may be (a+2b)*(a-2b). The third is (7y + 13z)*(7y - 13z). learn how to nicely known proper squares in this way of difficulty (distinction of proper squares): 4b^2 = (2b)^2 49y^2 = (7y)^2 169z^2 = (13z)^2

Answer 5

6x^3/4

Answer 6

What does the ^ mean in your question... and I'll be able to solve it for you.