2007-05-08 16:32:31 · 4 answers · asked by landaddy 1 in Science & Mathematics ➔ Mathematics
If every edge is 6 cm in an octahedron, then you can find the surface area by finding the area of eight equilateral triangles with an edge of 6cm.
The area of one of these equilateral triangles is 1/2(base)(height) = 1/2(6cm)(3 SQRT (3)) = 9 SQRT(3)
Since there are 8 triangles, the surface area is 72 SQRT (3)
2007-05-08 16:42:14 · answer #1 · answered by suesysgoddess 6 · 1⤊ 0⤋
Each face is an equilateral triangle with side = 6. Base is 6, height (using half the triangle) is √(6² - 3²) = √27 = 3√3. So the area of each face is half the base times the height, 3(3√3) = 9√3. There are 8 faces, so surface area is 72√3 ≈ 124.7 cm².
2007-05-08 16:45:03 · answer #2 · answered by Philo 7 · 0⤊ 0⤋
If 6 cm is the length of the side, the surface of one side is 6 x 6 = 36 cm squared. And the total surface is 36 x 6 = 216 cm squared. This is because the cube has 6 sides. Interestingly enough, the volume of this cube is 216 cm cubed. Because 6 x 6 x 6 (or 6 cubed) also equals 216.
2016-04-01 03:18:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The area of any face is 0.5 x 6 x 6(sqrt(3)/2), and there are 8 such faces.
2007-05-08 16:40:04 · answer #4 · answered by Anonymous · 0⤊ 0⤋