A 26 kg block is in equilibrium on an incline of 15 degrees. Find the normal force of the incline on the block in Newtons.
2007-05-08 12:00:49 · 4 answers · asked by elliot s 1 in Science & Mathematics ➔ Physics
cos(15)*m*g
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2007-05-08 12:09:12 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
Normal force = N = W cos(theta); where W = mg, the weight of the block of mass m = 25 kg. Theta is the incline angle = 15 deg. g = 9.81 m/sec^2 on Earth's surface. You can do the math.
Normal force is just a force perpendicular to whatever surface it is applied to. For example, when theta = 0 and there is no incline, N = W cos(theta) = W cos(0) = W; so the weight is in fact the normal force on a level ramp.
2007-05-08 19:16:24 · answer #2 · answered by oldprof 7 · 0⤊ 0⤋
Incomplete question go back to teacher and ask Where in Newtons? In his house? In his back yard?
Seriously
Getting your homework answered by someone else won't help you in the long run.
2007-05-08 19:10:02 · answer #3 · answered by Easy Peasy 5 · 0⤊ 1⤋
You are NOT smarter than a 5th grader. Just kidding, I have no idea what the answer either.
2007-05-08 19:09:02 · answer #4 · answered by SW1 6 · 0⤊ 1⤋