I need help with Physics!!!!?

Question

A 1.4 kg ball is dropped from the roof of a building 100 meters high. While the ball is falling to earth, a horizontal wind exerts a constant force of 12.0 Newtons on it. How far from the building does the ball hit the ground? how long does it take to hit the ground? what is its speed when it hits the ground?

Answer 1

Motion along vertical is independent of motion along horizontal direction

Initial velocity for vertical motion ' Uv'=zero
Distance through which it falls= 100 m
Acceleration(due to gravity)=9.8 m/s^2

Using, s=ut + (1/2)at^2 but u=Uv=zero, therefore

s=(1/2)at^2 and t= square root of [ 2s/a ]

t =square root of [ 2*100/9.8 ] = 4.5175 second

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Final velocity for vertical motion Vv=sq.rt of2*g*h

Vv= sq rt 2*9.8*100 =sq rt 1960=44.2718 m/s

Initial velocity for horizontal motion Uh=zero

Acceleration=force / mass = 12 /1.4=60/7 m/s^2

final velocity for horizontal motion Vh=Uh +at

but Uh=zero

therefore, Vh= (60/7)*4.5175=38.72 m/s

Final total velocity V=sq rt [Vh^2 + Vv^2]=58.82 m/s

The ball strikes the ground at a speed of 58.82 m/s
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Answer 2

We need to calculate how long the ball takes to hit the ground, and then calculate how far the wind pushes it during that time.

If we ignore the effects of wind resistance on the vertical falling, we can use the formula y = 0.5*g*t^2, where y is the given height of the building and g is the acceleration due to gravity, or 9.8 m/s^2. That works out to t = sqrt(2y/g), which you can calculate.

Now, given that the force acting on the ball is 12 N, we can find its acceleration. Remember, F = ma, so a = F/m. We know that F is 12 N and m is 1.4 kg, so you can calculate a. Then use x = 0.5*at^2, where you just calculated a and you calculated t above.