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If a rigid body contains points a,b, and c and is said to be rotating about c with an angular velocity of W

then


relative to 'b' whats the angular velocity


or in simpler words, if one were at rest with (or moving at the same speed as b) what would the angular velocity seem to be??

Please explain how you were able to visualize it( I have problem .... visualizing it)

2007-05-08 11:01:43 · 3 answers · asked by I want to delete my answers account 3 in Science & Mathematics Physics

3 answers

At the point 'c', the body is revolving around so that every point has a moment of I*w.
This concept helps viualize the motion. If I am at rest at C and try to slow the body down by grabbing a handle at point c then the Torque would be force times radius, which would then counteract the momentum of b w/r/t me at c equal to I*alpha of the body.

On the other hand, if I am at b, I am at rest w/r/t the body, so the point a has no relative motion w/r/t to me, therefore no angular momentum. So if I reached out from b to a the point a is already at rest w/r/t me.
Does that help?

j

2007-05-08 11:48:15 · answer #1 · answered by odu83 7 · 0 0

If the piece separates gently (and under no circumstances with an explosion as in case of a hearth cracker rocket ) then it really is going to fly part by part as no exterior rigidity has acted on the stone or the piece. So the most outstanding answer is determination a million. In case of an explosion halfway it really is going to remember on the point of separation. The small piece can pass in any random direction (no longer inevitably horizontal) and keep on with diverse parabolic route.

2016-11-26 20:06:12 · answer #2 · answered by arnie 4 · 0 0

that would put you on top...HI! was it good for you?

2007-05-15 18:39:43 · answer #3 · answered by blick 3 · 0 0

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