pick a card from a standard deck but do not replace it then pick a 2nd card what are the chances both are aces

Question

help! my math quiz corrections.

Answer 1

The chance you will get an ace on the first draw is 4/52 and the chance that will get an ace on the second draw is 3/51

multiply the two and you get
12/2652 I believe or .00452 or .452% chance

Answer 2

The chance that you will get the first ace is 4/52 or 1/13. Now because you removed the first ace (one card) to get another ace is 3/52 or 1/17. To find the probability of a dependent interaction, you must multiply the probability of the first action times the probability of the second action:
1/13 X 1/17 which is equivalent to 1/221.
That's the answer. One hundred percent sure.

Answer 3

for the first draw, the odds are one in 13, as there are 4 aces among 52 (unless you have a joker or two, that changes the odds to 4 in 53 or 2 in 27).

for the second draw (assuming the 1 in 13 has been successful), the odds are now 1 in 17 (or 3 in 52 for one joker and 3 in 53 for two).

that's a combined odds of 1 in 121 (1 in 13 times 1 in 17) for a jokerless deck (I'll let you do the multiplication if there are jokers).

Answer 4

50 - 50 either it is or it isnt