How can i write x^2 +4x -6 as (x-a)^2 +b ?

Question

I have a feeling that this has something to do with the difference of two squares, but cant exactly remember.

Please show some working out, i dont just want the answer

Answer 1

x^2 + 4x - 6 = (x - a)^2 + b
x^2 + 4x - 6 = x^2 - 2ax + a^2 + b

-2ax = 4x
-2a = 4
a = -2

x^2 + 4x - 6 = x^2 +4x + 4 + b
-6 = 4 + b
-10 = b

So, the solution is:

(x + 2)^2 - 10

Answer 2

= (x² + 4x + 4) - 4 - 6
= (x + 2)² - 10
= (x - (-2))² + (-10)
a = - 2 and b = - 10

Answer 3

x^2 + 4x - 6 = (x-a)^2 + b

you add and extract 10, by that the equation doesn't change:
x^2 + 4x - 6 + 10 - 10 = (x-a)^ + b

x^2 + 4x + 4 - 10 = (x-a)^ + b

(x+2)^ - 10 = (x-a)^ + b

And you obtain:
a = - 2
b = - 10

Answer 4

Im just gonna guess but dont take my answer seriously. Im just trying sum out... x^2=2x +4x = 6x - 6
+6 +6
okay I quit :D

Answer 5

(x+2)^2-10