What is the atomic mass sample of Diabloium?

Question

There has been a new chemical element found named Diabloioum. There are 3 common isotopes. The first 685Db has an atomic mass of 685.148 and is 92.563% naturally abundant. The next isotope 687Db has an atomic mass of 686.992 amu and is 5.261% naturally abundant, the last isotope 689Db has an atomic mass of 689.012 amu and is 2.224% naturally abundant. What is the atomic mass sample of Diabloium

Answer 1

atomic mass sample of Diabloium;
=1/100[(685.148 *92.563)+(686.992 * 5.261)+(689.012 *2.224)
=1/100[(63419.3543)+(3614.2649)+(1532.3626)
=685.6598 amu

Answer 2

isotopes are atoms that regulate indoors the form of neutrons of their nucleus. via utilising certainty the neutron is extremely exceedingly much an identical mass via utilising certainty the proton and electrically self sufficient, isotopes have very comparable chemical properties yet diverse atomic 1000's. maximum atoms have greater effective than one for constructive occuring isotope. working occasion carbon has carbon-12, carbon-13 and carbon-14. the isotopic 1000's are approximately 12, 13 and 14. yet pondering all of them have in certainty an identical chemistry, you in lots of situations decide to forget approximately on the difficulty of distinctive numbers of neutrons and ask what the mass of the "time-venerated" atom is. the atomic mass then is the time-venerated of the isotopic 1000's, weighted in accordance to their relative abundance interior the international. pondering maximum carbon is contained in this way of carbon-12, the atomic mass of carbon is amazingly close to to twelve (approximately 12.01).

Answer 3

This is just a weighted average problem:

M = (0.92563 * 685.148) + (0.05261 * 686.992) + (0.02224 * 689.012)

M = 634.19354 + 36.14265 + 15.32363 = 685.65982

M = 685.660 g/mole when rounded up to the proper number of signficant digits.

Answer 4

Confusing fanfic with reality can lead to confusion.