2007-05-08 05:10:36 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Let the age of A be 'a' and the age of B be 'b' at present.
assume that 'z' yrs before A was of the same as B is now. In other words, A is z yrs older than B now.
that is,
a - z = b
the present age of A is twice that of B 'z' yrs before.This means
a = 2 (b - z)
but b = a - z
therefore
a = 2 (a - z - z)
a = 2a - 4z
a = 4z
this gives
b = 4z - z = 3z
So A is 4z yrs old and B is 3z yrs old, z can be any whole number.
For example, if z is 1,
a = 4 and b = 3 and one year before, A was 3 yrs old and B was 2 yrs old. The pesent age of A is two times the age of B one year before.
hey! wait, a 4yr old Cannot be (practically) expected to ask this question. So z should be a bigger number.
who knows! these days kids are really smart and may be at age 4yrs itself they will start talking this mathematical language. Ha ha ha
2007-05-08 06:01:56 · answer #1 · answered by blue rose 2 · 0⤊ 0⤋
b is 18 and a is 12
2007-05-08 12:22:22 · answer #2 · answered by Anonymous · 0⤊ 1⤋
A is twice as old as B
A was as old as B
if
A=20 , B=10
then
A is twice as old as B
&
A was as old as B
.
2007-05-08 14:23:02 · answer #3 · answered by jiya k 1 · 0⤊ 0⤋
A=2b-b
2007-05-08 12:23:40 · answer #4 · answered by lionesspurnell 2 · 0⤊ 0⤋
Trinnnnnnnnnng! . I know the answer!!!, This thing is impossile to solve .
2007-05-08 12:22:26 · answer #5 · answered by Anonymous · 0⤊ 0⤋
umm 100 and 200 centuries old???
2007-05-08 12:19:02 · answer #6 · answered by dede 5 · 0⤊ 1⤋
the answer is Bx2-A
2007-05-08 14:49:40 · answer #7 · answered by Anonymous · 0⤊ 0⤋