2007-05-08 05:06:35 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
Because a photon moves at the speed of light and that speed is greater than the escape velocity of the surface of the Sun.
2007-05-08 06:06:21 · answer #1 · answered by Spilamilah 4 · 0⤊ 0⤋
The escape velocity from our Sun (the speed at which something must be launched in order for it to leave the Solar System) is high by our standards, but it's nothing compared to the huge speed of light. A photon must leave the sun at 617.5 km/s to escape, in fact it leaves at 300,000km/s so escaping the gravitational pull of the Sun is no problem!
2007-05-08 08:58:45 · answer #2 · answered by novadragonuk 1 · 0⤊ 0⤋
Photons are not pulled by gravity, only affected by the effects of gravity. So black holes have enough gravity to bend the space around them into themselves, and photons follow the space - but the Sun isn't any where near massive enough to do that, so the photons are emitted.
2007-05-08 05:26:19 · answer #3 · answered by eri 7 · 1⤊ 0⤋
"Light" is a particular form of energy. It is the form of energy that mass is composed of. This is seen when a negative and positive electron meet and they convert back into electromagnetic energy "light" at the gamma frequency. What once was mass becomes "light". Light does not become affected by the force of gravity but in a very slight degree. It does not lose its value of speed "c" even though moving in an intense field. It has an instantaneous speed of "c" away from the sun, moving at the same speed as the gravitons that would have to inhibit its passage. The net effect is zero.
2007-05-08 05:27:35 · answer #4 · answered by d_of_haven 2 · 0⤊ 1⤋
Simply put - very quickly.
Big as it is, the Sun doesn't have the 'pull' to trap a photon - only black holes have the sort of gravity that prevents an energy escape beyond the event-horizon.
2007-05-08 05:17:46 · answer #5 · answered by Anonymous · 1⤊ 1⤋
you're gazing too many giant call Trek reruns. no individual has shown the existence of a "graviton". Its a theoretical theory in accordance to theories that different elementary compelled are transmitted by the substitute of a subatomic particle from one atom to a unique. it really is likewise suggested by the actual shown truth that a photon (or an electron for that count) should be observed as both a particle or as a wave. Physicists theorize that gravity is created as a "bending" of area-time by the mass of the object. The imagine vast gravitational events (like supernovae) ought to reason gravity to "ripple" like a rock in a pond. If there are ripple (waves) then would the waves also be observable as a particle? tens of millions of bucks are getting used to create huge tanks of water in deep caverns with a view to no longer right now word such waves/debris, yet no individual have conclusively discovered any yet... in the experience that they discover them, THEN i will problem about how they get faraway from the black hollow...
2016-11-26 19:16:59 · answer #6 · answered by ? 4 · 0⤊ 0⤋
Rising against gravity makes things go slower, if they have any 'rest mass' at all, but light has none. Instead, the photon loses 'frequency', that is it 'redshifts', to a less energetic 'color' and corresponding longer wavelength.
Time runs slower in a gravity well, so imported or exported light has to adjust frequency to avoid temporal paradox.
2007-05-08 08:28:46 · answer #7 · answered by fhw 1 · 0⤊ 0⤋
The sun's gravity is nowhere near great enough to restrict the movement of something with as much energy as light.
2007-05-08 05:13:16 · answer #8 · answered by Brian L 7 · 1⤊ 0⤋
By exceeding the escape velocity of the surface of the sun.
2007-05-08 05:13:03 · answer #9 · answered by Jason T 7 · 1⤊ 0⤋
The gravity of the sun is not strong enough. If it is a black hole, then yes, it wouldn't escape.
2007-05-08 05:12:55 · answer #10 · answered by StandTall 4 · 0⤊ 0⤋