Factor This binomial difference of two cubes:?

0 ⤊

Factor This binomial difference of two cubes:?

27x^3 - 8

2007-05-08 04:41:43 · 3 answers · asked by Kevin M 1 in Science & Mathematics ➔ Mathematics

3 answers

The factoring pattern is:
A^3 - B^3 = (A-B)(A^2+AB+B^2)

In your problem, "27x^3 - 8," your A-value is 3x (since (3x)^3 = 27x^3), and your B-value is 2. So, plugging in those values, you get:

(3x-2)((3x)^2 + 3x * 2 + 2^2)

And simplifying, your final answer:

(3x-2)(9x^2+6x+4)

2007-05-08 04:51:18 · answer #1 · answered by Timothy H 4 · 0⤊ 0⤋

x^3=8/27
so x=2/3
so (x-2/3)(27x^2+18x+12)
or (3x-2)(9x^2+6x+4)

2007-05-08 04:53:47 · answer #2 · answered by bruinfan 7 · 0⤊ 1⤋

(a - b) (a^2 + ab + b^2)

2016-05-18 01:58:48 · answer #3 · answered by ? 3 · 0⤊ 0⤋