Write an equation of a line perpendicular to y= -3x+5 and has an x-intercept of -6.
2007-05-08 02:54:16 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The slope of your line is 1/3 and it passes through (-6,0) - ie the x-intercept
Write your line in slope-intercept form
2007-05-08 02:59:52 · answer #1 · answered by Orinoco 7 · 0⤊ 0⤋
the slope or any perpendicular line will have a slope equal to the inverse of the slope of the given line multiplied by -1
in this case, the given slope is -3, so the negative invserse slope = 1/3
using the y = mx+b equation, m = 1/3 and we also know that a point on the line is where is crosses the x axis at -6.
When the line crosses the x axis at -6, y will be 0
so: 0 = 1/3*(-6) + b
solving for b = 2
so the equation of the perpendicular line = y = 1/3x+2
2007-05-08 10:04:12 · answer #2 · answered by minorchord2000 6 · 0⤊ 0⤋
Find the equation of a line perpendicular to y = -3x + 5 and has an x -intercept of -6.
The equation of a line is
y = mx + b , where m is the slope and b is the x-intercept
A line is perpendicular to one another if the product of their slopes is negative one, that is....
m1 x m2 = - 1
We already know the slope of the first line, which is -3. To find the slope of the second line, substitute -3 to the equation.
-3 x m2 = -1
m2 = -1/-3
m2 = 1/3
Since this second line has slope 1/3 and x-intercept of -6,
the equation is==>
y = 1/3x - 6
2007-05-08 10:11:58 · answer #3 · answered by detektibgapo 5 · 0⤊ 0⤋
y = 1/3 x + 2
y = mx + b is the form so
slope m = -1/ original slope = -1 / -3 =1/3
1/3 (-6) + b = 0 so b = 2
2007-05-08 10:08:29 · answer #4 · answered by davec996 4 · 0⤊ 0⤋
Perpendicular â Negative inverse slope...
2007-05-08 09:58:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Both Minochord2000 and Davec996 are right but Minochord working's is clearer.
2007-05-08 10:51:27 · answer #6 · answered by tat2sailor 1 · 0⤊ 0⤋