Gas laws? How many moles of gas were collected?

0 ⤊

Gas laws? How many moles of gas were collected?

A gas evolved during fermentaion of sugar was collected at 22.5 degrees celcius and 702mmHg. After purification its volume was found to be 25.0L.

2007-05-07 22:48:51 · 4 answers · asked by confused! 1 in Science & Mathematics ➔ Chemistry

4 answers

PV=nRT
n=(0.92)(25.0)/(0.0821)(295.5)
n= 0.95 moles

2007-05-08 09:52:11 · answer #1 · answered by dandahamman 2 · 0⤊ 0⤋

(25.0 L)(293/295.5)(702/760)(1 mole/22.4 L) = 1.022176 moles

2007-05-08 05:58:22 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋

9.4806 moles

ideal gas law

PV=nRT
P = pressure = 702 mmHg = 0.92 atm
V = 25 L
n = ?
R = 0.0821(L*atm/mol*K)
T = 22.5 C = 295.5 K

PV=nRT
n=PV/RT
n=(0.92)(25.0)/(0.0821)(295.5)
n= 9.4806 moles

2007-05-08 06:56:41 · answer #3 · answered by ritche17 2 · 0⤊ 0⤋

0.095 mol.

2007-05-08 06:17:06 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 0⤋