when using the pythagorean theorem in a 45-45-90 triangle how would i find the side if two sides are 6/7?

Question

yep....the question pretty much says it all

Answer 1

c^2 = a^2 + b^2 (c is the hypotenuse and a and b are the other sides)

In this case, since we're trying to find the hyptenuse, all we do is square both sides and add them together. You also know that two sides are 45 degrees, they have to have the same length of 6/7.

c^2 = (6/7)^2 + (6/7)^2

c^2 = (36/49) + (36/49)

c^2 = 72/49

Just square root both sides and you get...

c = 1.2121...

Answer 2

Pythagoras's Theorem says that
a^2 + b^2 = c^2

It applies because your triangle is a right angled one. The 45-45-90 means it's isoceles.

If two sides are 6/7, then the are the two shorter sides are 6/7. So applying the theorem gives us

(6/7)^2 + (6/7)^2 = c^2
2 x (36/49) = c^2
72/49 = c^2
c = sqroot 72/49
= 1.212183....

Hope that helps :)

Answer 3

You didn't say whether 7 was the length of the hypotenuse.

(6^2) + (7^2)=c^2
36+49=c^2
85=c^2
c=9.22

But if 7 is the hypotenuse, then a or b would be as follows:

(a^2) + (6^2)=7^2
(a^2) + 36= 49
- 36 -36

a^2=13
a=3.6

Answer 4

If you have 45-45-90 triangle, and each of the 2 sides are 6/7
Then the hypotenuse = [6sqrt(2)] / 7

Answer 5

(6/7)^2 +(9/7)^2 =C^2
36/49 +36/49 = C^2
72/49 = c^2
C=6sqrt2/7

Answer 6

if the two side is a then the long side is a * the root of 2.